A family has 5 children. Compute the probabilities of the following events: All five are born on Friday.
Each one is born on a different day of the week.

1/16,807 chance that they all will be born on Friday

Probably 5/7, but don't take my word for it.

Step-by-step explanation:

There are 7 days of the week.

There is a 1/7 chance for one kid to be born on a certain day of the week.

We can attach an exponent of 5 since the 1/7 is a constant, and I'm not going to bother typing the same thing over and over again.

(1/7)^5 = 1/16,807.

The probability of all of them being born on Friday or anyday is 1/16,807.

The probability of each person being born on a different day of the week is  probabily going to be 5/7, but it could be different, because you need to factor in the requirement that they are not born on the same day.

I can guarantee that the first question is probably correct, but not the second.

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

x= cost per bracelet

number of bracelets * x + shipping charge = total cost

so

9x+9=72