Instant Dinner comes in packages with weights that are normally distributed, with a standard deviation of 0.5 oz. If 2.3% of the dinners weigh more than 13.2 oz, what is the mean weight?

12.2

Step-by-step explanation:

2.3%= 0.023

So that is the probability that it will be over 13.2 oz, or .977 is the prob that it will be below 13.2

z-score = (real score - mean)/standard deviation

I found .977 at a z-score of 2.00

so 2.00 = (13.2-m)/0.5

=> m=12.2

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic