Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the systems of equations to their solutions.
2x + y = 12
x = 9 − 2y
x + 2y = 9
2x + 4y = 20
x + 3y = 16
2x − y = 11
y = 11 − 2x
4x − 3y = -13
y = 10 + x
-3x + 3y = 30
2x + y = 11
x − 2y = -7
x = 2, y = 7
arrowRight
x = 5, y = 2
arrowRight
x = 3, y = 5
arrowRight
x = 7, y = 3
arrowRight

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !