Rewrite |3x+5|<or equals to 1 without absolute
value sign​

remember how the absolute value works:

|x| = x   if x ≥ 0

|x| = -x  if x < 0

Then we can rewrite:

|x| ≤ a

as:

-a ≤ x ≤ a

Now let's apply this to our case:

|3x + 5| ≤ 1

we can rewrite this as:

-1 ≤ 3x + 5 ≤ 1

We could solve this for x now, first subtracting 5 in the 3 sides:

-1 - 5 ≤ 3x + 5 - 5 ≤ 1 - 5

-6 ≤ 3x ≤ -4

now dividing by 3 in the 3 sides:

-6/3 ≤ 3x/3 ≤ -4/3

-2 ≤ x ≤ -(4/3)

So we rewrote the inequality without the absolute value part.

i dont know

step-by-step explanation:

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )