Which equation is the inverse of 5y+4=(×+3)^2+1/2?​

The inverse is -3 ±sqrt(5x+7/2)

Step-by-step explanation:

5y+4=(x+3)^2+1/2?

To find the inverse, exchange x and y

5x+4=(y+3)^2+1/2​

Solve for y

Subtract 1/2

5x+4 -1/2=(y+3)^2+1/2​-1/2

5x+8/2 -1/2=(y+3)^2+1/2​-1/2

5x+7/2 = (y+3)^2​

Take the square root of each side

±sqrt(5x+7/2) =sqrt( (y+3)^2​)

±sqrt(5x+7/2) = (y+3)

Subtract 3 from each side​

-3 ±sqrt(5x+7/2) = y+3-3

-3 ±sqrt(5x+7/2) = y

The inverse is -3 ±sqrt(5x+7/2)

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

homozygous. one is homozygous, while two is heterozygous.