`show that the normal to the parabola y²=8x at (2 4)meets the parabola again in(18, -12)`​

See Below.

Step-by-step explanation:

We want to show that the normal line to the parabola:

At the point (2, 4) meets the parabola again at (18, -12).

First, find the tangent line to the parabola at the point (2, 4). We can take the derivative of both sides with respect to x:

Implicit differentiation:

Therefore:

Then the slope of the tangent line to the point (2, 4) is:

Thus, the slope of the normal line is -1.

And since it passes through the point (2, 4), by the point-slope form:

Simplify:

By letting x = 18:

So, the normal line indeed passes through (18, -12).

answer is in the picture.

bottom left

step-by-step explanation:

the x's and the y's both go up the same amount each time, therefore it will be a linear function because it will go in a straight line when drawn on a graph.

hope this !

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.