Mathematics, 27.06.2021 18:10 Weaj01
Cos (2a) [tg (2a) - tg (a)] = tg (a) Es de identidades trigonométricas y realmente no entiendo ¿me ayudan?
Answers: 1
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(1)
(2)
![(\cos^{2}\alpha -\sin^{2}\alpha) \cdot \left[\frac{2- (1-\tan^{2}\alpha)}{1-\tan^{2}\alpha} \right]\cdot \tan\alpha = \tan \alpha](/tpl/images/1384/8311/a4c01.png)
![(\cos^{2}\alpha - \sin^{2}\alpha) \cdot \left[\frac{1+\tan^{2}\alpha}{1-\tan^{2}\alpha} \right] = 1](/tpl/images/1384/8311/2d545.png)
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Cos (2a) [tg (2a) - tg (a)] = tg (a) Es de identidades trigonométricas y realmente no entiendo ¿me a...
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