AQ'P'R' is an image created by a dilation centered at the origin with a scale factor k The vertices of AQ'P'R' are Q'(-2, 1), P(1,2), and R(-1,3). What are the coordinates of the vertices of the preimage AQPR?
A Q(-8, 4), P(4,8), R(-4, 12)
B. Q(-1, -2), P(-2, 1), R(-3,-1)
С. 1 1 11 1 3
Q1 2:4). P(4:2), R(47)
h
DQ(2, 1), P(-1,2), R(1.3)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

answer: c. is your answer

step-by-step explanation: get me a black leather coat