Mr. Alhammadi is shopping for school supplies with his children. Rashed selected 3 one-inch binders and 2 two-inch binders, which cost a total of 29 dirhams. Matar selected 5 one-inch binders and 2 two-inch binders, which cost a total of 35 dirhams. Write a system of equations that represents the above situation.

I need help ASAP please :(

3x + 2y = 29

5x + 2y = 35

Step-by-step explanation:

Let

x = cost of one-inch binders

y = cost of two-inch binders

Rasheed:

3x + 2y = 29 (1)

Matar:

5x + 2y = 35 (2)

3x + 2y = 29 (1)

5x + 2y = 35 (2)

Using elimination method, subtract (1) from (2)

5x - 3x = 35 - 29

2x = 6

x = 6/2

x = 3

Substitute x = 3 into (1)

3x + 2y = 29 (1)

3(3) + 2y = 29

9 + 2y = 29

2y = 29 - 9

2y = 20

y = 20/2

y = 10

the k side

step-by-step explanation:

plese mark mde brainliest!

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116