Given a line passes through point (5,8) and the origin, find the equation of the line.
y=

y=8/5x

Step-by-step explanation:

Hi there!

We need to find the equation of the line that passes through (5,8) and the origin (the point (0,0)).

There are 3 ways to write the equation of the line, although the most common way is slope-intercept form, or y=mx+b where m is the slope and b is the y intercept

first, let's find m (slope)

The formula for the slope calculated from two points is , where (,) and (, ) are points

we have two points, but let's label their values to avoid any confusion

=5

=8

=0

=0

now substitute into the formula

m=

m=

multiply

m=

divide

m=8/5

The slope of the line is 8/5

here's the equation so far

y=8/5x+b

now we need to find b

as the point will pass through both (5,8) and (0,0) we can use either one of them to solve for b

let's take (0,0) as an example

substitute 0 as x and 0 as y

0=8/5(0)+b

multiply

0=0+b

add

0=b

substitute 0 as b into the equation

Therefore the equation of the line is:

y=8/5x (the 0 is not necessary)

Hope this helps! :)

there is no points to select.

step-by-step explanation:

ιт ιѕ:

125.28

нσρє ι ¢συℓρ нєℓρ