Hola plz help i need this quick :) Quadrilateral ARMY is rotated 90 degrees about the origin. Draw the image of this rotation.

Step-by-step explanation:

If a point (x, y) is rotated 90° counterclockwise about the origin, rule for the rotation will be,

(x, y) → (-y, x)

Therefore, coordinates of the image point after the rotation will be (-y, x).

Following this rule,

Image points of the quadrilateral will be,

A(3, 3) → A'(-3, 3)

R(5, 7) → R'(-7, 5)

M(7, 5) → M'(-5, 7)

Y(5, 1) → Y'(-1, 5)

By graphing the image points we can get the graph of the image quadrilateral A'R'M'Y'.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)