The data set below provides the monthly rent (in dollars) paid by 5 tenants. 879 , 920 , 940 , 950 , 990 Suppose the rent for one of the tenants changes from $ 940 to $ 1115 . What is the mean before the rent changes? What is the mean after the rent changes?

Mean before the rent changes = $935.8

Mean after the rent changes = $970.8

Step-by-step explanation:

Mean = sum of all data values / number of data values in a given data set

✔️Data set consisting of the rents of 5 tenants: 879 , 920 , 940 , 950 , 990

Mean before the rent changes = (879 + 920 + 940 + 950 + 990)/5 = 4,679/5 = 935.8

Mean before the rent changes = $935.8

✔️If one of the tenants rent changes from $940 to $1,115, the new data set would be:

879 , 920 , 1,115 , 950 , 990

Mean after the rent changes = (879 + 920 + 1,115 + 950 + 990)/5 = 4,854/5 = 970.8

Mean after the rent changes = $970.8

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.

the answer is 15.50 for one mile

b) is slope: 0   y- intercept 15.5