Prove that
log a² - log b² = log (ab) log (a/b)​

Proof & Step-by-step explanation:

We know that log ab = log a + log b and log a/b = log a - log b, so we substitute that in and get (log ab)(log a/b) = (log a + log b)(log a - log b) = (log a)^2 - (log b)^2.

I hope this helps! If you have any questions, feel free to ask! :)

your welcome haha, this is the best place to find answers

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.