What is the equation of a line that contains the point (2,-5) and is parallel to the line y=3x-4

y = 3x - 11

Step-by-step explanation:

Parallel lines have the same slope so the relationship of x and y stays the same only the constant, b,  changes

y = 3x + b

plug in point (2, -5) to find "b"

-5 = 3(2) + b

-5 = 6 + b

subtract 6 from both sides

-11 = b

The equation is

y = 3x - 11

(2 , -5) are the points

then y =3x-x,let 4 be x

substitute 2&-5 in the line

-5 =3(2)-x

-5=6-x

-x=6 +5

=11

:x =-11

y=3x - (-11)

y =3x+11

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step-by-step explanation:

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