Company A is trying to sell its website to Company B. As part of the sale, Company A claims that the average user of their site stays on the site for 10 minutes. To test this claim Company B collects the times (in minutes) below for a sample of 12 users. Assume normality. Assignment 6q3 data Construct a 94% confidence interval for the true mean time spent on the web site. a) What is the lower limit of the 94% interval

Step-by-step explanation:

Given

See comment for data

Required

The lower limit 94% confidence interval

First, calculate the mean

Next, calculate the standard deviation using:

So, we have:

For 94% interval, the z score is

So, the margin of error (E) is:

The confidence interval of the true mean is:

The lower limit (L) is:

and the upper limit (U) is

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )