10) The second angle in a triangle is 3° less than twice the first angle. The third angle measure 8° more than twice the first angle Find each angle.

35, 67 and 78

Step-by-step explanation:

the angles are:

n, 2n-3 and 2n+8

there are 180 degrees in a triangle, so adding those terms together will give us 180

5n + 5 = 180

180 - 5 = 175

5n = 175

175 / 5 = 35

n = 35

now we have n we can put it in to the formula we have for the angles at the start:

n = 35

2n - 3 = 67

2n + 8 = 78

so the angles are

35, 67 and 78

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°