Find r if 0=pi/6 rad sector 64m^2

Given:

Area of a sector = 64 m²

The central angle is .

To find:

The radius or the value of r.

Solution:

Area of a sector is:

Where, r is the radius of the circle and is the central angle of the sector in radian.

Putting , we get

Taking square root on both sides, we get

Therefore, the value of r is m.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

the answer is two. hope this !