PLEASE HELP MEE!! 50 POINTS URGENT

The function y= x^2-10x+31 has a _ (minimum, maximum) value of __ (5, 10, 31, 6)

minimum value of 6

Step-by-step explanation:

Given

y = x² - 10x + 31

with a = 1, b = - 10

Since a > 0 then the function has a minimum value

The minimum value is the y- coordinate of the vertex.

The x- coordinate of the vertex is

x = - = - = 5

Substitute x = 5 into the function for y- coordinate of vertex

y = 5² - 10(5) + 31 = 25 - 50 + 31 = 6

The function has a minimum value of 6

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question