A small airplane takes off from point A and continues to climb upward in a straight line, as shown in the diagram. What is the plane’s distance from point A when it reaches point C? A. 6,900 feet
B. 7,000 feet
C. 11,636 feet
D. 12,600 feet
E. 13,400 feet

Ahh um shît

Step-by-step explanation:

I think b but mainly leaning wit d

Explanation:

We have two similar triangles here, so we can set up the proportion below to solve for x

5200/(5200+6500) = 5600/x

5200/11700 = 5600/x

5200x = 11700*5600 cross multiply

5200x = 65,520,000

x = (65,520,000)/(5200)

x = 12,600 which shows why the answer is choice D

side note: 12,600 ft = 2.386 miles approximately

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?