A 21-inch rope is to be cut into two pleces so that one piece is 8 inches longer than twice the other. How long is each piece, if a=2, b= 8, and I=21 smaller plece
in
larger plece

4 1/3 inches   Smaller piece

16 2/3 inches   Larger piece

Step-by-step explanation:

x + (2x + 8) = 21

3x + 8 = 21

3x = 13

x = 13/3

x = 4 1/3 inches   Smaller piece

2x + 8 = 8 2/3 + 8

2x + 8 = 16 2/3 inches   Larger piece

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!