Consider a single spin on the spinner shown below. A circle is split into sections 1, 2, 4, and 3. A spinner is pointing at number 2. Sections 1 and 2 are shaded. Which events are mutually exclusive? Check all that apply. landing on an unshaded portion and landing on 2 landing on a shaded portion and landing on 3 landing on a shaded portion and landing on an even number landing on an unshaded portion and landing on a number greater than 3 landing on a shaded portion and landing on an unshaded portion

The answer is "Options A, B, and E represent mutually exclusive events".

Step-by-step explanation:

Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.

In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.

In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.

In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.

In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.

In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.