Simplify (2 − + 1) + 5 and find its value for a = -2.

Part A

a·(a² - a + 1) + 5·a = a³ - a² + 6·a

Part B

The value of a·(a² - a + 1) + 5·a, for a = -2 is -24

Step-by-step explanation:

Part A

The given function is a·(a² - a + 1) + 5·a

The function is simplified by expanding the product of sums into sums of products, as follows;

a·(a² - a + 1) + 5·a = a × a² - a × a + a × 1 + 5·a = a³ - a² + a + 5·a = a³ - a² + 6·a

The function, a·(a² - a + 1) + 5·a, in simplified format is therefore;

a·(a² - a + 1) + 5·a = a³ - a² + 6·a

Part B

When a = -2, we get;

(a³ - a² + 6·a) = (-2)³ - (-2)² + 6·(-2) = -8 - 4 - 12 = -24

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

the k side

step-by-step explanation:

plese mark mde brainliest!