Evaluate each function following the specification.

#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2

b. No restrictions for all real numbers

b. Yes, x ≠ 2

Step-by-step explanation:

#3 The function is given as g(x) = -x² + 3

a. From the given function, by plugging in the value of 'x' in the bracket, we have;

g(-1) = -(-1)² + 3 = -1 + 3 = 2

g(-1) = 2

g(0) = -0² + 3 = 3

g(0) = 3

g(1) = -1² + 3 = -1 + 3 = 2

g(1) = 2

g(-1) = 2, g(0) = 3, and g(1) = 2

b. The given function g(x) = -x² + 3 for finding the value of g can take any value of x which is a real number

Therefore, therefore, there are no restrictions

#4 a. The given function is given as follows;

By substitution, we get;

b. From the values of the function, we have that h(x) is not defined at x = 2

Therefore, there is a restriction for x in the function, which is x ≠ 2

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step-by-step explanation:

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