On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 1), point B is at (3, 2), and points C is at (negative 1, negative 1) If line segment BC is considered the base of triangle ABC, what is the corresponding height of the triangle?

0.625 units

0.8 units

1.25 units

1.6 units

D. ( LAST ONE ) 1.6 UNITS

Step-by-step explanation:

IF (x₁,y₁) ,(x₂,y₂) AND (x₃,y₃) ARE THE VERTICES OF THE TRIANGLE.

THEN THE AREA OF THE TRIANGLE IS

HERE x₁= -1,y₁=1 ,x₂=3,y₂=2, and x₃= -1,y₃=-1

THEN THE AREA OF THE TRIANGLE IS

=4 square units

BC is base of the triangle.

Then the length of BC is =

= 5 UNITS

Let the height of the triangle be x.

We know that

The area of triangle is

1/2 x base x height

= (1/2x5xX) square units

According to the problem,

1/2 x 5 x X=4

-  X =  4x2/5

X=1.6 UNITS

Therefore the height of the triangle is 1.6 units.

$18 was the price of the t-shirt

step-by-step explanation:

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42