Twenty percent of all telephones of a certain type are submitted for service while under warranty. Of these, 60% can be repaired, whereas the other 40% must be replaced with new units. If a company purchases ten of these telephones, what is the probability that exactly four will end up being replaced under warranty

0.0052 = 0.52% probability that exactly four will end up being replaced under warranty.

Step-by-step explanation:

For each telephone, there are only two possible outcomes. Either they are replaced under warranty, or they are not. The probability of a telephone being replaced under warranty is independent of any other telephone, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

Twenty percent of all telephones of a certain type are submitted for service while under warranty. Of those, 40% are replaced.

This means that

Company purchases ten of these telephones.

This means that

What is the probability that exactly four will end up being replaced under warranty?

This is P(X = 4). So

0.0052 = 0.52% probability that exactly four will end up being replaced under warranty.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

where are the images of the functions i can only see the question you typed.

step-by-step explanation: