The mean birth weight for children born in a certain country at full term (after 40 weeks) is 3500grams; the standard deviation for birth weight is 500 grams. The shape of the distribution is symmetric and unimodal. About 34% of the weights are between what two values?

About 34% of the weights are between 3280 grams and 3720 grams.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 3500 grams, standard deviation of 500 grams.

This means that

About 34% of the weights are between what two values?

Between the 50 - (34/2) = 33rd percentile and the 50 + (34/2) = 67th percentile.

33rd percentile:

X when Z has a p-value of 0.33, so X when Z = -0.44.

67th percentile:

X when Z has a p-value of 0.67, so X when Z = 0.44.

About 34% of the weights are between 3280 grams and 3720 grams.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

answer: answer is b.

[m < b = 120º]

step-by-step explanation: