because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote. x2 + 12x + 27
x2 + 4x + 3
.
Mathematics, 23.06.2021 03:30 Angelanova69134
Find the dicontinuities of the function.
f(x) =
x2 + 12x + 27
x2 + 4x + 3
.
There is a removable discontinuity at
(
,
).
Answers: 2
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You know the right answer?
Find the dicontinuities of the function.
f(x) =
x2 + 12x + 27
x2 + 4x + 3
.
x2 + 12x + 27
x2 + 4x + 3
.
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