2) When Janet put her marble collection in groups of 7 there were two marbles left over, when she put them in groups of 5 there were 3 marbles left over. What is the fewest number of marbles that Janet could have had in her collection?​

23 marbles

Step-by-step explanation:

3 groups of 7 = 21 +2 = 23

4 groups of 5 = 20 +3 = 23

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )

try soting them out first

step-by-step explanation: