A hole of radius 2 inches is bored through the center of a right cylinder with radius 6 inches and height 10 inches. What is the total surface area of the resulting solid? Express your answer in terms of π.

184π in.²

Step-by-step explanation:

The total surface area of the resulting solid = the total surface area of the cylinder - the area of the two ends of the hole

✔️Total surface area of the cylinder = 2πr(r + h)

Where,

r = 6 inches

h = 10 inches

Total surface area of the cylinder = 2*π*6(6 + 10)

= 12π(16)

= 192π in.²

✔️Area of the two ends of the whole = 2(πr²)

Where,

r = 2 inches

area = 2(π*2²)

= 2(4π)

= 8π in.²

✔️The total surface area of the resulting solid = 192π - 8π

= 184π in.²

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%