Joseph leans a 20-foot ladder against a wall so that it forms an angle of 69° with the ground. How high up the wall does the ladder reach? Round your answer to the
nearest hundredth of a foot if necessary.

18.67 ft

Step-by-step explanation:

     |\

     |   \

     |      \

h    |         \     20 ft

     |            \

     |               \

     |--        69°  \

     ---|

For the 69° angle, h is the opposite leg, and 20 ft is the hypotenuse.

sin A = opp/hyp

sin 69° = h/20

h = 20 * sin 69°

h = 18.67

18.67 ft

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.