Suppose the mean height for men is 70 inches with a standard deviation of 2 inches. What percentage of men are between 68 and 74 inches tall? Enter
the value of the percentage without the percent sign.

81.85.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Suppose the mean height for men is 70 inches with a standard deviation of 2 inches.

This means that

What percentage of men are between 68 and 74 inches tall?

The proportion is the p-value of Z when X = 74 subtracted by the p-value of Z when X = 68.

X = 74

has a p-value of 0.9772.

X = 68

has a p-value of 0.1587.

0.9772 - 0.1587 = 0.8185

0.8185*100% = 81.85%.

Thus the percentage is 81.85%, and the answer is 81.85.

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step-by-step explanation:

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yo answer should be 6 if im not mistaken

step-by-step explanation: