Triangle PQR has vertices P(-2, 6), Q(-8, 4) and R(1, -2). It is translated according to the rule (x, y)—> (x, - 2, y -16). What is the y-value of P’?

a. -18

b. -16

c. -12

d. -10

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To find this answer, you apply the given translation rule to the coordinates of point P(-2,6)

We see that point P' has a y coordinate of -10

This translation, aka shifting, rule moved point P 2 units to the left and 16 units down.

233,100

step-by-step explanation:

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: