A garden that is 14 feet by 17 feet will have a pedestrian pathway on the border, making the combined area of the garden and the border 311 square feet what is the width of the pathway

The width of the pathway is 5.2 feet

Step-by-step explanation:

Given that the shape of the garden and the walkway is a rectangle, the walkway would have the same length as the garden but would have it's own width.

Let the width of the garden be W and that of the walkway be t while the length of both the garden and walkway is L. The combined area A

= L( W + t)

Given that the combined area of the garden and the border 311 square feet while the garden is  14 feet by 17 feet

311 = 14 (17 + t)

311 = 238 + 14t

collect like terms

14t = 311 - 238

14t = 73

t = 73/14

= 5.2 feet

the answer would be c:   ax + b = ax + c

step-by-step explanation:

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles