On a coordinate plane, polygon S prime T prime U prime V prime has points (negative 2, 4), (negative 4, 1), (negative 2, negative 2), and (0, 1). Given the dilation rule DO,1/3 (x, y) → (one-third x, one-third y)

and the image S'T'U'V', what are the coordinates of vertex V of the pre-image?

Idon't see any graph, however the graph of the function : f(x) = x²-2x+3 is a parabola: 1) open upward (since a> 0)2) it intersects y-axis in 3 (y=3)3) its axis of symmetry is x = +1 ( -b/2a)4) it's minimum is y = -2, so its vertex is (1,-2)5) it doesn't intersect the x-axis since discriminant < 0