ABDE is a rectangle ed is 8cm BDC is a right-angled triangle bc is 4.5cm ABC is a straight line the area of the rectangle abde is 40cm^2 work out the area of the triangle BDC also I need working out so

11.25cm^2

Step-by-step explanation:

given the area of the rectangle as 40cm^2, we can get the width of the rectangle.

Area =Length x width

40cm^2 = 8cm x width

we can divide both sides 8 to be left with the width

40/8 = 5cm

so the width is 5cm which is equal to the height of the triangle.

Area of BDC = 1/2 x base x height

BDC = 1/2 x 4.5 x 5

=11.25cm^2

there are no figures how am i supposed to answer this question

step-by-step explanation: