The quantity p varies inversely as the square of (q + 2)
p=5 when q = 3
Find p when q = 8​

p = 1.25

Step-by-step explanation:

varies inversely

p (q + 2)² = k

Find k

p=5 when q = 3

5(3 + 2)² = k

5(25) = k

125 = k

Find p when q = 8​

p(8 + 2)² = 125

p(100) = 125

divide both sides by 100

p = 1.25

18.36. give me brainliest!

step-by-step explanation:

you have to multiply 1.53 by 12 so the equation is 12x1.53 and then that is your answer.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)