The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 72 cm, what is the length of the diagonal?
The length of the diagonal is
cm.
Give your answer to 2 decimal places.

Step-by-step explanation:

W=2L-2

A=72

LW=72

L(2L-2) = 72

2L^2 -2L= 72

2L^2 -2L-72=0

L^2 - L -36 = 0

L= -5.52 or 6.52(neg # not a solution)

W=11.04

L=6.52

DIAG = = 12.82

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im sorry but no. i just need to answer for 50 poonts oof

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find the upper bound of the range.

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step-by-step explanation: