THIS IS THE THIRD PROBLEM I NEED HELP WITH

A = (-5, 3)

B = (-4, 8)

C = (0, 9)

D = (0, 2)

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.