A business student is interested in estimating the 90% confidence interval for the proportion of students who bring laptops to campus. He wishes a precise estimate and is willing to draw a large sample that will keep the sample proportion within seven percentage points of the population proportion. What is the minimum sample size required by this student, given that no prior estimate of the population proportion is available

n = 106

Step-by-step explanation:

Given  

p = 0.5 and 1-p = q = 0.5

Margin of error = 0.08  

Confidence level = 90%  

Z score for 90% confidence level =     1.65

As we know -  

Margin of error = z * Sqrt (pq/n)

Substituting the given value, we get –  

0.08 = 1.65 * Sqrt (0.5*0.5/n)

Squaring both the sides and solving, we get  

n = 1.65^2*0.5^2/0.08^2

n = 106.34 = 106

  or  

step-by-step explanation:

if the four friends split the cost, p, of the pizza evenly, then each friend pays one-fourth of the cost of the pizza.

the expression is   or  

answer: yard ramps with a level off platform are typically 36 feet long. truck, rather than at an angle, enabling access to those pallets at the very back of the truck. if you are using your yard ramp to convert a loading dock into a drive-in door, we even at 60 inches (5 feet) high and a 30 foot ramp, the slope of the ramp will be less

step-by-step explanation: