The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 378 people entered the park, and the admission fees collected totaled 1,042.00 dollars. How many children and how many adults were admitted?

188 children, 190 adults

Step-by-step explanation:

For this equation, let c be the number of children, and a represent the number of adults.

On this day 378 total people were at the park, so

a + c = 378   eq 1

Each adult pays $4, so the admission fee for ALL adults will be $4 multiplied by the number of adults , a, so 4a

Use the same method for the children, and the total all children paid is 1.50c

From all the children and adults, the total was 1042, so merge the 2 cost variables together.

4a + 1.50c = 1042   eq 2

the 2 equations we will use are

a + c = 378

4a + 1.50c = 1042

From equation 1, subtract c from both sides, and

a = 378 - c     eq 3

Substitute the value of a in eq 3 into equation 2

4a + 1.50c = 1042

4 (378 - c) + 1.50c = 1042

1512 - 4c +1.50 c = 1042 (collect like terms)

1512 - 1042 = 4c -1.50 c

470 = 2.5 c

c = 470 /2.5

c = 188 children

Substitute the value of c into eq 3 to get the value of a

a = 378 -c

a = 378 - 188

a = 190 adults

step-by-step explanation:

compare

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.