If g(x) = 4x2 - 16 were shifted 9 units to the right and 1 down, what would the new equation be? A. h(x) = 4(x + 9)2 – 17 B. h(x) = 4(x – 9)2 – 17
C. h(x) = 4(x = 17)2 - 9
D. h(x) = 4(x - 7)2 + 16​

Step-by-step explanation:

If you move down 1 unit, you simply subtract 9 units from the given equation.

g(x) = 4x^2 - 16 - 1

g(x) = 4x^2 - 17

Shifting right is a little bit tricky. To shift right, you have to do the opposite of what you would do on the number line. The x has to become x - 9 because the x value (you will learn later) is part of a distance and distances always subtract one from the other.

The wrong way to do it is in answer A.

B is the correct answer

h(x) = 4(x - 9)^2 - 17

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

happy to

pls mark as brainliest

option (a)

step-by-step explanation:

step 1:   take 2 number whose product equal to 25..

and sum of those two number are -10

step: 2 for example here if we take 5,5 are the number,,

5*5=25

and

5+5=10

but we need -10

so if we take   -5,-5

so -5*-5=25

and -5+(-5)=-10

s0

come the equation

replace -10x by these number

like -5x -5x+25

take common

x(x-5)-5(x-5)=0

(x-5)(x-5)=0