Suppose the mean of 15 suppose the mean of 15 numbers in a data set is 30. If the number 58 is included as an additional data value, what would be the new mean? Record the result below accurate to two decimal places.

New Mean:

88.00

Step-by-step explanation:

(a+b+c+x+y+...+z)/15=30

(a+b+c+x+y+...+z) is the 15 numbers

(a+b+c+x+y+...+z+58)/16=88

a+b+c+x+y+...+z+58=1408

a+b+c+x+y+...+z=1350

(1350+58)/16=88

To two decimal places? I would put the answer as 88 but I guess it would be 88.00...? Sorry if it's wrong, but I hope this helps a little! :)

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.