Find the number of sides of a regular polygon if exterior angle of the polygon is:- (a) 90 (b) 45 (c) 12 (d) 4

8 sides

Step-by-step explanation:

THE QUESTION IS NOT COMPLETE, SO A QUESTION OF THE SAME TYPE

Find the number of sides of a regular polygon if exterior angle of the polygon is 45°?

NOTE:

Sum of the exterior angles of any regular polygon is known as (360°)

But from the question,

Each exterior angle is given as( 45°)

Number of sides of a regular polygon can be computed as

(360°/Each exterior angle)

Then substitute the give value of exterior angle, we have

= (360°/45) = 8 sides

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0