Mathematics, 18.06.2021 02:30 chrisdelreal86

Help ASAP please plz

Answers: 1

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Answer from: Cheyenneross366

Step-by-step explanation:

surface area: 1/2 x 20ft. x 32ft. x 4 + 32ft. x 32ft.

=2304ft.^2 or 2034sq. ft.

area of one triangle: 1/2 x 20ft. x 32ft.

=320ft.^2 or 320 sq. ft.

Answer from: luvcherie18

Part A
The area of one triangular face of the square pyramid is 320 square feet:

As shown in the net, use the side length 32 ft from the square face as the base of a triangle.

Use formula 1/2 • base • height to find the area of one triangular face:
1/2 • 32 • 20 = 320
FINAL ANSWER: The area of one triangular face is 320 square feet.

Part B
The surface area of the square pyramid is 2,304 square feet.

Add up area of each face in the net:
Area of the square base: 32 • 32 = 1,024
AREA- 1,024 square feet

We know that the area of one triangular face is 320 square feet. Since we have 4 triangular faces, we will multiply 320 by 4:
320 • 4 = 1,280

ADD area of squara base and area of 4 triangular faces:
1,024 + 1,280 = 2,304
FINAL ANSWER: the surface area of the square pyramid is 2,304 square feet

HAVE A NICE DAY!
(Brainliest will be appreciated)
-SpaceMarsh

Answer from: Quest

All points to the left of zero on a horizontal number line are negative. a number line is a picture of a graduated straight line that serves as abstraction for real numbers. this number line can be extended to the left to represent numbers which are smaller than 0. such numbers are called negative numbersmark me brainliest

Answer from: Quest

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

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