A tank contains 1000L1000L of brine with 20kg20kg of dissolved salt. Pure water enters the tank at a rate of 15L/min.15L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. Answer the following questions. 1. How much salt is in the tank after tt minutes

there is 15 amount of salt in the tank after t minute.

Step-by-step explanation:

Given the data in the question;

tank contains 1000L of brine with 20kg of dissolved salt, Pure water enters the tank at a rate of 15L/min.

How much salt is in the tank after t minutes.

Now,

let x represent the amount of salt after t minutes,

so

x(0) = 15

dx/dt = rate in - rate out

Now, since the water entering is pure, the rate in is 0

rate out will be; x/1000 × 10 kg

∴

dx/dt = -x/100

dx = -dt

∫dx =  -∫1dt + c

lnx =  - + c

Now since x(0) = 15

ln15 = c

lnx =  - + ln15

x =

x = 15

Therefore, there is 15 amount of salt in the tank after t minute.

the first one

step-by-step explanation:

just id the test.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: