Amanda, Bryan, and Carl are about to compete in 100 mixed IM swimming events. These are the only three
swimmers competing in this event. They are all working
hard to win first place.
How many different possible ways could the 3 swimmers
place?
2

9514 1404 393

  6

Step-by-step explanation:

Any of the three can be in first place.

Any of the remaining two can be in 2nd place.

The remaining swimmer will be in 3rd place.

There are 3 × 2 × 1 = 6 possible orderings of the swimmers.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !