A right triangle has side lengths 5, 12, and 13 as shown below. Use these lengths to find tanB, sin B, and cos B. (WORK INCLUDED GIVING BRAINLEST TO BEST ANSWER)​

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Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relationships.

  Sin = Opposite/Hypotenuse   ⇒   sin(B) = 12/13

  Cos = Adjacent/Hypotenuse   ⇒   cos(B) = 5/13

  Tan = Opposite/Adjacent   ⇒   tan(B) = 12/5

child does not get an education so she can use the molla on junk

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true