What is the degree of the simplest polynomial with integer coefficients that has √2 , 2 , √2 + i , and 2 + 2i as some of its zeros? a. 6
b. 7
c. 8
d. 9

If the polynomial has integer coefficients, then any complex roots with non-zero imaginary part must occur along with their conjugates. If a + bi is a root, then so is a - bi.

The given polynomial would then have at least 6 roots: √2, 2, √2 + i and √2 - i, and 2 + 2i and 2 - 2i. So the minimum degree is (A) 6.

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.