The function f (x)= ax^2+bx+c, determine a, b and c knowing that the graph passes through the points (1,0), (0,)) and (-1,2).

a= 1

b= -1

c=0

equation looks like x²-x

Step-by-step explanation:

we have

ax²+bx+c

we know that when x=1 y=0 so plugging in 1 for x means

(doing this for the other points we get)...

a+b+c=0

c=0

a-b+c=2

Because we know c=0 we can write

a+b=0

a-b=2

Adding the two equations

2a=2

a=1

Knowing that a=1 we can easily solve for b

a+b=0

1+b=0

b= -1

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation: