Choose the function with the largest constant of variation? A 2-column table with 5 rows. Column 1 is labeled x with entries 1, 2, 3, 4, 5. Column 2 is labeled y with entries 2, 4, 6, 8, 10. A 2-column table with 5 rows. Column 1 is labeled x with entries 2, 4, 8, 12, 16. Column 2 is labeled y with entries 0.5, 1, 2, 3, 4. On a coordinate plane, a line goes through points (0, 0) and (1, 3). On a coordinate plane, a line goes through points (0, 0) and (2, 2).

A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.

Step-by-step explanation:

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A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.

ok then what happened.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204